The chords AB and CD intersect at P. AB=17 centimetres, PA=9 centimetres,
PD=12 centimetre
(a) What is the length of PB?
(b) Find the length of PC.
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Answer:
Given, AB and DC are chords
AP=12PB=6
PC=2DP=?
then,
AP×PB=PC×PD
12×6=2×PD
PD=36
mark me as a brainlest please
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