The chords AB and CD of a circle are perpendicular to each other. If radius of the circle is 35 cm and the length of the arc BPC is 30cm, find the length of arc AQD. (Assume π = 22/7 )
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Answer:
8.5 cm
Step-by-step explanation:
we know that when two chords of a circle intersect either inside or out side then the area of the rectangle formed by the segments of one chord is equal to the area of the rectangle formed by the segments of the other.
So in this let CD = x cm
Then AE × BE = CE × DE
ie. 14×3 = (x+3.5)×3.5
So x+3.5 = 14×3/3.5 => x+3.5 = 4×3
So x= 12 - 3.5 = 8.5. so CD = 8.5 cm
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