Question

The Chs baseball team was on the field and the batter popped the ball up. The equation b(t) = 80t - 16t+3.45 represents the height of the ball above the ground in feet as a function of time in seconds. How long will the catcher have to get in position to catch the ball before it hits the ground?

Answer 1

Answer:

t =  0.1 ± √(53)/40i     where i = √(-1)

Step-by-step explanation:

                       CASE (1)

Given

Height as the function of time = B(t) = 80t² -16t + 3.45                .....(1)

When ball hits the ground the height of ball will zero

So

putting B(t) = 0 in equation (1) we get

80t² - 16t + 3.45 = 0

80t² -16t + 69/20 = 0

1600t² -320t + 69 = 0

by using Quadratic Formula

t =  0.1 ± √(53)/40i              where i is the complex number equal to √(-1).

Hence in this case t =  0.1 ± √(53)/40i

                             CASE (2)

When

B(t) = 80t -16t + 3.45 = 64t + 3.45

Then

Putting B(t) = 0 for zero Height we get

64t +3.45 = 0

t = -3.45 /64

So in this case t = -3.45 /64 which is negative number