Question

The ci on a certain sum for 2 years is 105 and si is 100. Find the sum

Answer 1

difference between CI and si = 5

time = 2year

Si = prt/100

10000 = 2rp

pr = 5000

Now

Ci = p(( 1 + r/100)^2 - 1))

105 = p{ ( 1+ 50/p)^2 -1)

105 = p{ 1+ 2500/p^2 + 100/p -1)

105 = 2500/p + 100

5p = 2500

p = 500

So

r = 10 %

Sum = D(100/r)^t

sum = 5(100/10)^2

sum = 500

Answer 2

difference between CI and si = 5

difference between CI and si = 5 time = 2year

difference between CI and si = 5 time = 2year Si = prt/100

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rp

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 100

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500So

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500So r = 10 %

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500So r = 10 %Sum = D(100/r)^t

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500So r = 10 %Sum = D(100/r)^tsum = 5(100/10)^2

difference between CI and si = 5 time = 2year Si = prt/10010000 = 2rppr = 5000Now Ci = p(( 1 + r/100)^2 - 1))105 = p{ ( 1+ 50/p)^2 -1)105 = p{ 1+ 2500/p^2 + 100/p -1)105 = 2500/p + 1005p = 2500p = 500So r = 10 %Sum = D(100/r)^tsum = 5(100/10)^2sum = 500