The CI on a certain sum for 2 years is Rs 41 and SI is 40rs . THEN the rate per annum is
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Let the principal be = P
rate of interest = t
time n = 2
We have CI = P(1+t )² - P = 41 ---- (1)
SI = P*t*2=40
= P*t = 20 ---- (2)
Solving (1) P(1+t²+ 2t) -P =41
⇒ P + Pt² + 2Pt - P= 41
⇒ Pt(t + 2) = 20 (t+2) = 41 substituting value of t from (2)
⇒ t +2 = 41/20
⇒ t = 1/20= 5/100= 5%
Rate per annum is 5%
rate of interest = t
time n = 2
We have CI = P(1+t )² - P = 41 ---- (1)
SI = P*t*2=40
= P*t = 20 ---- (2)
Solving (1) P(1+t²+ 2t) -P =41
⇒ P + Pt² + 2Pt - P= 41
⇒ Pt(t + 2) = 20 (t+2) = 41 substituting value of t from (2)
⇒ t +2 = 41/20
⇒ t = 1/20= 5/100= 5%
Rate per annum is 5%
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