The circle concentric with
x² + y2 + 4x +6y +3= 0 and radius 2 is
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Let the concentric circle be x^2 +y^2 +4x+6y+k=0
Radius =v(4+9-k)=2
=13-k =4
K=9
Therefore the equation of a circle be x^2 +y^2 +4x+6y+9=0
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