Question

The circle passing through origin and
making intercepts 6 and - 4 on x and y-
axes respectively has the centre
(A) (3,-2)
(B) (-2,4)
(C) (8,-4
(D) Both A and B​

Answer 1

Step-by-step explanation:

Let S=x2+y20+2gx+2fy=0 be the equation of circle which passes through origin

C=(−g,−f),r=g2+f2

Given that it makes intercept of 4 with x-axis

⟹4=2r2–d2

Where d is distance between center and chord

⟹2=g2+f2–f2

g=±2

Similarly

⟹2=g2+f2–g2

g=±4

Equation of circle is

x2+y2±4x±8y=0