Math, asked by Pratheeka123, 9 months ago

The circle through the points (2,3), (2,2), (3,2)

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Answers

Answered by MaheswariS
1

\underline{\textbf{Given:}}

\textsf{Points are (2,3), (2,2) and (3,2)}

\underline{\textbf{To find:}}

\textsf{The equation of the circle passing through the points}

\mathsf{(2,3),(2,2)\;and\;(3,2)}

\underline{\textbf{Solution:}}

\textsf{We can find a circle passing through any three non-collinear points}

\textsf{Let the equation of the requiredcircle be}\;\mathsf{x^2+y^2+2g\,x+2f\,y+c=0}-------(1)

\textsf{Since the circle (1) passes through (2,3), we have}

\mathsf{2^2+3^2+2g(2)+2f(3)+c=0}

\mathsf{4+9+4g+6f+c=0}

\mathsf{4g+6f+c=-13}--------(2)

\textsf{Since the circle (1) passes through (2,2), we have}

\mathsf{2^2+2^2+2g(2)+2f(2)+c=0}

\mathsf{4+4+4g+4f+c=0}

\mathsf{4g+4f+c=-8}--------(3)

\textsf{Since the circle (1) passes through (3,2), we have}

\mathsf{3^2+2^2+2g(3)+2f(2)+c=0}

\mathsf{9+4+6g+4f+c=0}

\mathsf{6g+4f+c=-13}--------(4)

\underline{\textsf{Solving (2) and (3):}}

\mathsf{(2)-(3)\;\implies}

\mathsf{4g+6f+c=-13}--------(2)

\mathsf{4g+4f+c=-8}--------(3)

\implies\mathsf{2f=-5}

\implies\boxed{\mathsf{f=\dfrac{-5}{2}}}

\underline{\textsf{Solving (3) and (4):}}

\mathsf{(3)-(4)\;\implies}

\mathsf{4g+4f+c=-8}--------(3)

\mathsf{6g+4f+c=-13}--------(4)

\implies\mathsf{-2g=5}

\implies\boxed{\mathsf{g=\dfrac{-5}{2}}}

\mathsf{Using\;f=\dfrac{-5}{2}\;and\;g=\dfrac{-5}{2}\;in\;(3)}

\mathsf{4\left(\dfrac{-5}{2}\right)+4\left(\dfrac{-5}{2}\right)+c=-8}

\mathsf{2(-5)+2(-5)+c=-8}

\mathsf{-20+c=-8}

\mathsf{c=20-8}

\implies\boxed{\mathsf{c=12}}

\textsf{Equation of the required circle is}

\mathsf{x^2+y^2+2\left(\dfrac{-5}{2}\right)\,x+2\left(\dfrac{-5}{2}\right)\,y+12=0}

\boxed{\bf\,x^2+y^2-5x-5y+12=0}

\underline{\textbf{Find more:}}

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