Question

the circle with centre(3÷2,1÷2)and radius root 3/2 is

Answer 1

Here it is given that centre (h,k)=(

2

1

,

4

1

) and radius r=

2

1

Therefore the equation of the circle is

(x−

2

1

)

2

+(y−

4

1

)

2

=(

12

1

)

2

⇒x

2

−x+

4

1

+y

2

−

2

y

+

16

1

=

144

1

⇒x

2

−x+

4

1

+y

2

−

2

y

+

16

1

−

144

1

=0

⇒144x

2

−144x+36+144y

2

−72y+9−1=0

⇒36x

2

+36y

2

−36x−18y+11=0