Question

The circle with Centre O is divided into three sectors are shown in the figure Centre angle at the first sector 60 degree if we put a dot inside the circle without looking into it what is the probability of being in the first sector

Answer 1

Answer:

Total outcome = 360°

Favourable outcome = 60°

Probability = 60

360

= 1

6

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Answer 2

Answer:

the probability of a random dot being in the first sector of the circle is 1/6.

Given:

circle with Centre O is divided into three sectors

The central angle of the first sector = 60°

To find:

the probability of a random dot being in the first sector of the circle.

Solution:

we know that 'O' is the center of the circle.

a complete angle = 360°

the central angle of the first sector = 60°

let the probability of a random dot being in the first sector of the circle be x.

x = area of the first sector/ total area

since the central angle of the circle is 60/360 of the complete circle, we can say that the area of the first sector is 60/360 of the circle as well.

x = 60/ 360

x = 1/6

Hence, the probability of a random dot being in the first sector of the circle is 1/6.

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