Question

The circle with centre (x, y) passes through
the points (3, 11), (14, 0) and (12, 8). Find
the values of x and y.​

Answer 1

Answer:

Step-by-step explanation:

Let the given points be A(3,11), B(14,0) and C(12,8).

Suppose the coordinate of centre of the circle be O(   x   ,   y   ).

∴ OA = OB = OC (Radius of the circle)

OA 2   = OB 2   = OC 2

(x-3)2 +(y-11)2=(x-14)2+(y-0)2=(x-12)2 +(y-8)2

=x2 +196-28 x +y 2 =x2-40x  +208 +y2

12x=12

x=1

So, (x−3)2+(y−11)2=(x−14)2+(y−0)2

⇒(1−3)2+(y−11)2=(1−14)2+(y−0)2    [As x=1]

⇒4+y 2+121−22 y=169+y 2

⇒−44=22 y

⇒y=−2 So, x=1 and y=−2

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Answer 2

Answer:

Step-by-step explanation:

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