Question

The circle x2 + y2 + 4x - 7y + 12 = 0 cuts an
intercept on y-axis equal to-


Answer:)
f=(-7/2),c=12
now formula= 2✓f^2-c
putting value of 'f' and 'c'
we get:)
=2✓(-7/2)^2-12
=2✓(49/4)-12
=2✓(1/4)
=2×1/2
=1
answer=:'1'​

Answer 1

By using formula,

$2 \sqrt{f {}^{2} - c }$

Here, f =7/2 and c = 12

So,

$2 \sqrt{(7 \div 2) {}^{2} - 12 }$

$2 \sqrt{1 \div 4}$

$2 \times 1 \div 2 = 1$

So, Answer is 1.