The circuit containing a battery of 5 volt and 3 resistance of 5 ojm 8 ohm 12 ohm in any possible arrangements of the resistance the maximum current that can flow through the 5 ohm resistance is
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there can be following possibilities..
1) R net = 5+8+12 ohm ...series
= 25 ohm
V/ R = I
I = 5 / 25 = 0.2 ( minimum)
2) 1/Rnet = 1/5 +1/8 +1/12
1/Rnet = (24+ 15 + 10)/120 = 49/ 120
Rnet = 120/49 = 2.44
I max = 5 / 2.44 = 2 ..... ...so your answer is 2
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