Physics, asked by saonijain782, 11 months ago

The circuit has two oppositively connected ideal diodes in parallel. What is the current flowing in the circuit?(a) 1.71 A(b) 2.00 A(c) 2.31 A(d) 1.33 A

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Answers

Answered by tishuuu
0
5/6+1/4..
10/12+3/12
13/12
Answered by Anonymous
1

Answer:

Explanation:

The P -N junction as diode  is a one way device. It offers a low resistance when forwardly biased and high resistance when reversely biased.

wherein

R = 0, Forward  

R = ∞ Reverse

Diode D1 is reversed biased, so it offers an infinite resistance. Sp no current flows in the branch of diode D1

Diode D2 is forward biased, so it offers no resistance in the. Sp no current flows in the branch of diode D2

Thus,

In the figure D, is reverse biased, thus no current will flow through D.

I = V/R

I = 12/ 4+2ohm

I = 12/6

I = 2 ohm

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