The circuit in figure shows the two cells connected in opposition to each other. the cell of EMF 6 volt and internal resistance 2 ohm, the cell E2 is of EMF 4 volt and internal resistance 8 ohm find the potential difference between a and b
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E1*r2-e2*r1/r1+r2
=6*8-4*2/10
=4
=6*8-4*2/10
=4
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