Question

The circuit layout is given. The power of the voltage source P
E
​
=-50 W, power of the current source P
J
​
= -50 W. What will these powers be if the resistance value R is increased by 2 times? E,J=const.

Answer 1

Answer:

The circuit layout is given. The power of the voltage source Pe=-50 W, power of the current source Pj= -50 W. What will these powers be if the resistance value R is reduced by 2 times? E,J=const. J >> E R 1. P_E= -50 W, P_J= -50 W 2. P E= -50 W, P_J=-150 W 3. P_E= 0 W,P_J= -50 W 4. P E= -50 W, P_J= 0 W 5. P_E= 50 W, P_J= 0 W

Explanation:

I hope it helps you

Answer 2

The value of power when the value of resistance is doubled is -25 W.

Given,

The power of the source = -50 W

A resistance R and a voltage source V.

To Find,

The value of power if the value of resistance R is increased by 2.

Solution,

The formula for calculating the power of a circuit is

P = V²/R = -50 W-----(i)

where,

P is the power, V is the voltage, and R is the resistance of the circuit.

Now, the value o resistance is increased 2 times

So,

P' = V²/R'

Now, R' = 2R

P' = V²/2R

Now, substituting the value from equation (i)

P' = 1/2(P) = 1/2(-50) = -25 W

Hence, the value of power is -25 W.

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