The circular head of the screw gauge is divided into 20 divisions and the screw moves 1 mm ahead in two rotations of the head of the screw. Find its least count.
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SOLUTION
GIVEN
- DiViSiON = 20
- Screw moves 1 mm ahead in 2 rotation.
CALCULATION
- Pitch = Distance / No. of Rotation
- Pitch = 1mm / 2
- Pitch = 0.5 mm
- Least Count = Pitch / No. of Division
- Least Count = 0.5 / 20
- Least Count = 0.025 mm
RESULTS
- Least Count of screw gauge is 0.025 mm
Answered by
2
Answer:
SOLUTION
GIVEN
DiViSiON = 20
Screw moves 1 mm ahead in 2 rotation.
CALCULATION
Pitch = Distance / No. of Rotation
Pitch = 1mm / 2
Pitch = 0.5 mm
Least Count = Pitch / No. of Division
Least Count = 0.5 / 20
Least Count = 0.025 mm
RESULTS
Least Count of screw gauge is 0.025 mm
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