Question

the circular portions of the following figure are semicircles forcrach of the following figures.
please tell me the answer faster ​

Answer 1

Answer:

You have using mobile or pc or iphone.There must be a calaculator.Calculate it yourself.

Step-by-step explanation:

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Answer 2

Answer:

(i) Area = 353.429 m²

(ii) Perimeter = 77.12 m

Step-by-step explanation:

We know that,

Width of the track is 30 m and total length is 42 m.

Now,

We are told that, those two are semicircles, which has a width or diameter of 30m

Thus, its Radius = D/2 = 30/2 = 15 m

(Now to understand it better I have posted an image, please do refer it.)

Now,

(i) Area of Semicircle = (πr²)/2

= (3.14 × 15 × 15)/2

= (706.858)/2

= 353.429 m²

(ii)

Here we must be careful because, they have asked us the total perimeter of the semicircle,

We know that,

Perimeter of the semicircle = arc(AEC) + AC

We know that,

Arc AEC is a semicircle so its perimeter = (2πr)/2

= πr

= 3.14 × 15

= 47.12 m

AC = 30 m (Diameter)

Thus,

Perimeter of the semicircle = 30 + 47.12 = 77.12 m

Hope it helped and you understood it........All the best