Question

the circular scale of a screw gauge contains 100 divisions and its pitch is 1 mm. Give the least count of the screw gauge

Answer 1

Least count = pitch/total no. of divisions in circular scale
=0.01cm/100 =1*10^-4cm
=0.01mm....

Answer 2

Answer:

The least count of the screw gauge is 0.01 mm.

Explanation:

• Screw Gauge: A screw gauge is used to measure the width of any object, which is thin.

                               Two parameters are involved to screw gauge, which needs to be measured, they are - pitch and least count.

• Pitch: Pitch of a screw gauge is the ratio of distance moved by a screw to the number of rotations.
• Least count: Least count of a screw gauge is the ratio of pitch and number of divisions the circular scale contains.
• Least count = $\frac{pitch}{Number of divisions }$

        Here pitch = 1 mm and number of divisions = 100

        Least count = 1/100 mm = 0.01 mm

       ∴ The least count of the screw gauge is 0.01 mm.