the circular scale of a screw guage contains 100 divisions and its pitch is 1mm.Give the least count of the screw guage
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0.01mm is the least count may be.
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hello mate here is ur ans
since no of division are 100
and pitch is 1mm
therefore we have
least count =pitch ÷ total no of division
= 1÷100= 0.01mm
hence the. ans is 0.01mm
#############be brainly###########
since no of division are 100
and pitch is 1mm
therefore we have
least count =pitch ÷ total no of division
= 1÷100= 0.01mm
hence the. ans is 0.01mm
#############be brainly###########
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