Question

the circular whose radius is 3 units and whose Centre lies on the original the co-ordinate of any point lies on the circle and the on the x-axis are ​

Answer 1

Answer:

Correct option is

A

x

2

+y

2

−8x−14y=0

(x−h)

2

+(y−k)

2

=r

2

Here (h,k)→ centre

Equation of line through centre

k=h−1−−−−(1)

& (x,y) point on circle

So, given (x,y)=(7,3)

So, (7−h)

2

+(3−h+1)

2

=3

2

Using eqn (1)

We get,

28+h

2

−11h=0

h=7 oR 4

k=6 oR 3

Equation of circle corresponding (7,6)

x

2

+y

2

−14x−12y+76=0

Equation of circle corresponding (4,3)

x

2

+y

2

−8x−6y+16=0