The circular wooden floor of diameter 2.8mis to be polished. If the rate of polishing is 200pesqm find the total cost of polishing
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d=2.8 m
So, r=1.4m
Area of wooden floor = πr^2
= 22/7 ×1.4 ×1.4
=6.16 sq. m
Rate of polishing 1 sq. m = rs 200
Therefore, rate of polishing 6.16 sq. m
= 200 × 6.16
= Rs 1232
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