The circumcenter of triangle abc is o.prove that angle obc+angle bac=90
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Let
Angle OBC = x°
Angle BAC = y°
Now,
We know that we can draw a circle around triangle as it's centre be circumcentre which touchcs corners of triangle:-
Draw a picture as shown in attachment,
In triangle OBC
OB = OC
So,
Angle OBC = Angle OCB = x°
Now,
Consider Arc BC,
We know that. An arc subtended twice of angle at circum when compared to centre,
Therefore,
Angle BAC = 2× angle BOC = 2y
Now,
in Triangle OBC
Sum of Angels = 180°
2y + x + x = 180°
x + y = 90°
or,
Angle OBC + Angle BAC = 90°
Angle OBC = x°
Angle BAC = y°
Now,
We know that we can draw a circle around triangle as it's centre be circumcentre which touchcs corners of triangle:-
Draw a picture as shown in attachment,
In triangle OBC
OB = OC
So,
Angle OBC = Angle OCB = x°
Now,
Consider Arc BC,
We know that. An arc subtended twice of angle at circum when compared to centre,
Therefore,
Angle BAC = 2× angle BOC = 2y
Now,
in Triangle OBC
Sum of Angels = 180°
2y + x + x = 180°
x + y = 90°
or,
Angle OBC + Angle BAC = 90°
Attachments:
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