the circumcentre of the triangle formed by (0,0),(2,-1) and (-1,3) is (5/2,5/2) then the orthocentre is
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Answer:
Correct option is
D
(
2
−1
,
2
7
)
Circumcentre of ΔABC
A(1,2);B(−2,2),C(1,5)
ΔABC is right angle at 'A', so
circumcentre is mid-point of BC
⇒C=(
2
1+(−2)
,
2
2+5
)
=(
2
−1
,
2
7
).
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