The circumcentre of the triangle formed by (0,0), (8,0), (0,6)is
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Answer:
24units
Step-by-step explanation:
by distance formula,
let A(0,0) ,B(8,0),C(0,6)
AB=square root of (0-8)^2+(0-0)^2
= square root of 64
=8 units
BC=square root of (8-0)^2+(0-6)^2
=square root of ( 64+ 36)
=square root of 100
= 10 units
AC= square root of (0-0)^2+(0-6)^2
= 6 units
circumference or perimeter of
triangleABC=AB+BC+AC
= 8+10+6
= 24 Units
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