The circumcentre of the triangle formed by (1,-2),
(-2,4) and (3,-6)is
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Explanation:
let the three given coordinates be A B and C
A=(1,-2),B=(-2,4)&C=(3,-6)
AB=√{1-(-2)}²+(-2-4)²=√9+36=√45
BC=√(-2-3)²+{4-(-6)}²=√25+100=√125
CA=√(3-1)²+{-6-(-2)}²=√32
now the circumference will be the sum of these lengths
AB+BC+CA=√45+√125+√32=3√5+5√5+5√2
=8√5+4√2
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