The circumference if a circle is 7cm longer than the perimeter of a regular inscribed hexagon Find the circumference
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Step-by-step explanation:
Since ABCDEF is an inscribed regular hexagon.
So each interior angle of it ={(n-2)*180°}÷n
={ (6–2)* 180°}÷ 6 = 720° /6 = 120°
So, each angle will be bisected into 60° ( as each triangle is congruent to other)
As the central angle is equally divided into 6 angles each measuring 60°
This way each triangle is an equuilateral triangle.
So, in triangle OAB, OA = OB = AB = r , where r is the radius of the circle.
Now, PERIMETER of regular hexagon = 6r
As per the condition given ,
Circumference = 7 + 6r
2 pi r = 7+ 6r
=> 2 pi r - 6r = 7
=> 2*(22/7)* r -6r = 7
=> r{(44/7) -6} =7
=> r*(2/7) = 7
=> r= 49/2
Now, circumference = 2*pi*r
= 2*(22/7) * (49/2)
= 154 cm………ANS
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