Math, asked by onyxsangma, 18 days ago

The circumference of a circle exceeds the diameter by 16.8 cm. Find the circumference of a circle.​

Answers

Answered by hogwartian
1

Answer:

Circumference = 8.21 cm

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Answered by ItzMeSam35
1

 \mathfrak{Given :-}

 \mathfrak{Circumference = Diameter + 16.8 cm}\\

 \mathfrak{To Find :-}

 \mathfrak{Circumference}\\

 \mathfrak{Solution :-}\\

 \mathfrak{Circumference \:  = Diameter  \:  +  \: 16.8 \: cm}

 \mathfrak{Circumference \:  =  Radius \:  +Radius\:  +  \: 16.8 \: cm}

 \mathfrak{Circumference \:  =  2 \: Radius \:  +  \: 16.8 \: cm}

 \mathfrak{2 \: \pi \: r \:  = 2 \: r \:   +  \: 16.8 \: cm}

 \mathfrak{2 \: \pi \: r \:  -  \: 2 \: r \:  =  \: 16.8 \: cm}

 \mathfrak{r \: (2 \: \pi \:  -  \: 2) \:  =  \: 16.8 \: cm} \\

 \mathfrak{r \times (2 \: \pi \:  - 2) = 16.8 \: cm}

 \mathfrak{r \:  \times (2 \times  \frac{22}{7} - 2) = 16.8 \: cm }

 \mathfrak{r \:  \times( \frac{44}{7} - 2) = 16.8 \: cm  }

 \mathfrak{r \:  \times ( \frac{44 - 14}{7} ) = 16.8 \: cm}

 \mathfrak{r \:  =  \frac{16.8 \times 7}{30} \: cm }

 \mathfrak{r \:  =  \frac{117.6}{30} cm}

 \mathfrak{r \:  = 3.92 \: cm}

 \mathfrak{Circumference \:  = 2 \: \pi \: r}

 \mathfrak{Circumference \:  = 2  \: \times \frac{22}{7}  \:  \times 3.92 \: cm }

 \mathfrak{Circumference \:  = 24.64 \: cm}

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