Math, asked by rajeshrijoshi1985, 8 months ago

the circumference of a circle is 22.find the area and also find the area of circle​

Answers

Answered by amankumaraman11
1

 \sf \: Circumference \:  of  \: a \:  circle =  2\pi r = 22 \: (unit) \\  \\  { \boxed{\sf   = >    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:2 \times  \frac{22}{7} \times r  =22 }} \\  \\ { \boxed{\sf   = >    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:   r =  \frac{22}{2} \times  \frac{7}{22}  }} \\  \\ { \boxed{\sf   = >    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:r =  \frac{7}{2} \:  (unit)}}

Now,

{ \boxed{ \huge{ \tt{ Area   \: \: of  \: \: a  \:  \: circle = \pi {r}^{2} }}}} \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \:  \:  \:  \:  \frac{22}{7}  \times  ( \frac{7}{2} )^{2}  \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:=  \frac{22}{7}  \times  \frac{7}{2}  \times  \frac{7}{2}  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{22 \times 7}{2 \times 2}  =  \frac{154}{4}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: { \boxed{\sf = 38.5 \:  \:  {(unit)}^{2} }}

Answered by Anonymous
1

\huge{\underline{\underline{\blue{\mathfrak{Answer \: : }}}}}

Given :

Circumference of the circle is 22 cm.

________________________

To Find :

Area of circle

_______________________

Solution :

We know that,

\large{\boxed{\red{\sf{Circumference \: = 2 \pi r}}}}

22 = (2 * 22 * r)/7

⟹ 22 * 7 = 44 * r

⟹ 154 = 44 * r

⟹ 154/44 = r

⟹ r = 3.5 cm

\large{\boxed{\green{\sf{Radius \: (r)= 3.5 \: cm}}}}

\rule{200}{2}

Now,

\large{\boxed{\pink{\sf{Area \: = \pi     r^2}}}}

(Putting Values)

⟹ Area = (22 * 3.5 * 3.5)/7

⟹ Area = (22 * 12.25)/7

⟹ Area = 269.5/7

⟹ Area = 38.5 cm²

\large{\boxed{\orange{\sf{Area = 38.5 \: cm^2}}}}

\rule{200}{2}

#answerwithquality

#BAL

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