Question

the circumference of a circular Garden is 1012 meters find the area of outside the garden a road of 3.5 metre with runs around it calculate the area of the road and find the cost of levelling it at the rate of 32 Paisa per square metre​

Answer 1

since the circumference of circular garden =572m

⇒2πr=572

⇒2.7/22.r=572

⇒r=91m

=r+3.5m

=91+3.5

=94.5m

Hence, the area cover up by the road;

=πr, 2-πr2

=πr, 2-πr2=7/22 (94.52-91)

=2040.5m²

given that the cost of reparing the road at the rate of Rs375per100sq.m

then the total cost for repairing the road

= 100/375x2040.5

$Rs7651.88$