the circumference of a circular garden is 572 m. outside the garden a road of width 3.5m runs around it. calculatethecoast of reparing the road at the rate of rs . 3.75 per sqare meter.
Answers
Question :
The circumference of a circular garden is 572 m. outside the garden a road of width 3.5 m runs around it. Calculate the cost of repairing the road at the rate of rs . 3.75 per square meter.
Solution :
2πr₂ = 572
r₁ = 572 / 2 × 22 × 7
r₁ = 91 m
r₂ = r₁ + width of Road
= 91 + 3.5 = 94.5 m
Area of Road = πr₂²- πr₁²
= 22/7 [( 94.5)² - (91)²
= 22/7 [8930.25 - 8281]
= 2040.5 m²
Total cost = 2040.5 × 3.75
= 7651.875 Rs.
Answer:
2πr₂ = 572
r₁ = 572 / 2 × 22 × 7
r₁ = 91 m
r₂ = r₁ + width of Road
= 91 + 3.5 = 94.5 m
Area of Road = πr₂²- πr₁²
= 22/7 [( 94.5)² - (91)²
= 22/7 [8930.25 - 8281]
= 2040.5 m²
Total cost = 2040.5 × 3.75
= 7651.875 Rs.