the circumference of a circular Park is 264 M and 3.5 M Wide Road runs on the outside around 8 find the cost of constructing the road at rupees 200 per square metre.
Answers
Answered by
61
circumference=264m
264m=2πr
2*22/7*r=264m
r=(264*7/2*22)m
r=42m
radius of park=42m
width of road=3.5m
so,
outer radius=42m+3.5m
=45.5m
now,
area of park=πr*r
=22/7*42m*42m
=5544sq metre
whole area=area of field+area of road
=πR*R
=22/7*45.5m*45.5m
=6506.5sq m
area of road=whole area-area of field
=6506.5sq m-5544sq m
=962.5sq m
cost for constructing road =rupees200* area of road
=rupees200*962.5
=rupees192500 answer
264m=2πr
2*22/7*r=264m
r=(264*7/2*22)m
r=42m
radius of park=42m
width of road=3.5m
so,
outer radius=42m+3.5m
=45.5m
now,
area of park=πr*r
=22/7*42m*42m
=5544sq metre
whole area=area of field+area of road
=πR*R
=22/7*45.5m*45.5m
=6506.5sq m
area of road=whole area-area of field
=6506.5sq m-5544sq m
=962.5sq m
cost for constructing road =rupees200* area of road
=rupees200*962.5
=rupees192500 answer
Answered by
7
ANSWER:-
RUPEES 192500
HOPE IT HELPS!!
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