Math, asked by divyanshinandanwar, 5 months ago

The circumference of a circular park is 314m. A 20 M. wide concrete track runs round it. Calculate the cost of laying turf in the park at 1.25 per sq.m. and the cost of concrete track at 1.25 per sq.m .


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Answers

Answered by blackskull66
5

Answer:HI good morning dear dearThis is your answer

The cost of laying turf in the park is Rs.9812.5 and the cost of concreting path is Rs.376800

Step-by-step explanation:

Circumference of circular park =2 \pi r = 2 \times \frac{22}{7} \times r2πr=2×

7

22

×r

We are given that the circumference of a circular Park is 314 m

So,2 \times 3.14 \times r =3142×3.14×r=314

r=\frac{314 }{2 \times 3.14}r=

2×3.14

314

r=50

Area of park =\pi r^2 = 3.14 \times 50^2 = 7850 sq.m.πr

2

=3.14×50

2

=7850sq.m.

Cost of laying turf in park in 1 sq.m. = Rs.1.25

Cost of laying turf in 7850 sq.m. =1.25 \times 7850 =Rs.9812.51.25×7850=Rs.9812.5

A 20 metre wide concrete track is made around it

Outer radius = 50 m +20 m = 70 m

Area of track = Outer area - Inner area = \pi R^2 - \pi r^2 = 3.14(70^2-50^2)=7536 sq.m.πR

2

−πr

2

=3.14(70

2

−50

2

)=7536sq.m.

Cost of concreting 1 sq.m. path = Rs.50

Cost of concreting 7536 sq.m. path = Rs.50 \times 7536=Rs.376800Rs.50×7536=Rs.376800

Hence the cost of laying turf in the park is Rs.9812.5 and the cost of concreting path is Rs.376800

Answered by Anonymous
2

Answer:

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