the circumference of a circular park is 660m. A 7m wide path surrounds it.Find the cost of fencing the outer boundary at the rate of rupees 60 per metre.
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Answer:
2πr=660
so,r=660/2π
so,r=105
so outer radius=105+7=112
so circumference=2π×112=(2×22×112)/7=704m^2
so per metre square cost Rs60
so704meter square =704×60=Rs42240
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