Question

the circumference of a circular playground is 528m find the total expenditure of repairs of the ground at the rate of Rs 1.50 per square metre (π =22/7) step by step explanation​

Answer 1

Answer:

2πr= 528

2×22×r= 7 ×528

r=84m

πr²= 22/7×84= 12×22=220+44= 264cm²

so total expentidure is 1.5 × 264 ₹