the circumference of a circular playground is 528m find the total expenditure of repairs of the ground at the rate of Rs 1.50 per square metre (π =22/7) step by step explanation
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Answer:
2πr= 528
2×22×r= 7 ×528
r=84m
πr²= 22/7×84= 12×22=220+44= 264cm²
so total expentidure is 1.5 × 264 ₹
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