Question

the circumference of a circular pond is 47.08m.find the surface area of the pond

Answer 1

Answer:

$2\pi \: r = 47.08 \\ r = \frac{47.08}{2\pi} \\ = \frac{47.08 \times 7}{2 \times 22} \\ = 7.49 \\ area \: is \: \pi {r}^{2} = \frac{22}{7} \times {7.49}^{2} = 176.3146 \: squre \: m$