Question

The circumference of a circular track is 264 m. If a path of width 7 m is laid around and the inside the track then the area of the ring is

Answer 1

Circumference of inner circle = 2πr

264 = 2*22/7*r

r= 42 m

Area of inner circle = πr^2 = 22/7*42*42 = 5544 m^2

Radius of outer circle = 42 + 7 = 49m

Area of outer circle = πR^2 =22/7*49*49= 7546 m^2

Area of track = Area of outer circle - Area of inner circle = 7546-5544 = 2002 m^2