Question

The circumference of a semicircular design is 72cm find its area​

Answer 1

HEY MATE ..!!!!

circumference of a circle =

$2\pi r$

Therefore, circumference of a semicircle=

$\pi \: r$

=> 72 =

$\pi \: r$

72/

$\pi$

= r

72÷22/7= r

72×7/22 = r

22.9 = r

Now, Area of circle=

$\pi \: {r}^{2}$

Therefore, area of semicircle=

$\pi {r}^{2} \div 2$

=>22× (22.9)^2

--------------------------

7 × 2

=> 22× 524.41

--------------------

14

= 11537.02

-----------------

14

= 824.07

${cm}^{2}$

Hope it helps you......!!!!