Question

The circumference of circle exceeds its diameter by 16:8 cm. Find its circumference of the circle

Answer 1

let diameter of the circle be 'd' cm
$circumference \: of \: a \: circle \\ exceeds \: the \: diameter \: by \: \frac{16}{8}$

$i.e \: it \: exceeds \: by \: 2cm$
CIRCUMFERENCE=DIAMETER +2cm

$we \: know \: that$

$circumference = \pi d$
$\pi d = d + 2cm$

$\frac{22}{7} \times d = d + 2cm$

$\frac{22d}{7} = d + 2cm$

$22d = 7(d + 2)$

$22d = 7d + 14$

$22d - 7d = 14$

$15d = 14$

$d = \frac{14}{15}$

$d = 0.94cm$

$circumference = \pi d$

$= \frac{22}{7} \times 0.94$

$= 22 \times 0.134$

$= 2.94cm$

THEREFORE,
THE CIRCUMFERENCE OF THE CIRCLE IS 2.94 cm.

$hope \: this \: helps$