The circumference of circle exceeds its diameter by 18 cm. Find the radus of circle
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Answered by
4
Hey mate..
________
Given,
The circumference of a circle exceed its diameter by 18 cm
So,
2πr = d + 18
=) πd = d + 18. ( °•° 2r = d )
=) πd - d = 18
=) d ( π - 1 ) = 18
=) d ( 22/7 - 1 ) = 18
=) d ( 22 - 7 / 7 ) = 18
=) d × 15 / 7 = 18
=) d = 18 × 7 / 15
=) d = 7 × 2
=) d = 14 cm
As,
d = r / 2
Thus, r = 7 cm
The required radius is 7cm
Hope it helps ✓✓
________
Given,
The circumference of a circle exceed its diameter by 18 cm
So,
2πr = d + 18
=) πd = d + 18. ( °•° 2r = d )
=) πd - d = 18
=) d ( π - 1 ) = 18
=) d ( 22/7 - 1 ) = 18
=) d ( 22 - 7 / 7 ) = 18
=) d × 15 / 7 = 18
=) d = 18 × 7 / 15
=) d = 7 × 2
=) d = 14 cm
As,
d = r / 2
Thus, r = 7 cm
The required radius is 7cm
Hope it helps ✓✓
Róunak:
Plz tell moderator to provide me an edit option
Answered by
5
let the diameter of circle be 2r cm and radius be r cm
C= 2πr
it is given that the diameter is exceed by 18
2πr = d+18
πd = d+18
πd-d = 18
d(π-1) = 18
d(3.14-1)=18
d(2.14)=18
d=18/2.14
d=8.41cm
hence,
r=d/2
r=8.41/2
r=4.20cm
thanks for watching the answer.
C= 2πr
it is given that the diameter is exceed by 18
2πr = d+18
πd = d+18
πd-d = 18
d(π-1) = 18
d(3.14-1)=18
d(2.14)=18
d=18/2.14
d=8.41cm
hence,
r=d/2
r=8.41/2
r=4.20cm
thanks for watching the answer.
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