The circumference of four wheels are 50cm, 60cm, 75cm and 100cm respectively. They start moving simultaneously. What least distance should they cover so that each wheel makes complete number of revolutions?
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Simple do L.C.M. of 50,60,75,100.
5 |50,60,75,100
3 |10,12,15,20
2 |10,4,5,20
2 |5,2,5,10
5 |5,1,5,5
|1,1,1,1. so least common multiple of these 4 numbers =5×3×2×2×5=300 . So distance travelled =2π(300)=600π=1884cm approximately .
5 |50,60,75,100
3 |10,12,15,20
2 |10,4,5,20
2 |5,2,5,10
5 |5,1,5,5
|1,1,1,1. so least common multiple of these 4 numbers =5×3×2×2×5=300 . So distance travelled =2π(300)=600π=1884cm approximately .
justarandomteen123:
thanks!
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