Question

the circumference of second orbit of h atom if the wavelength of electron is 5 into 10 power minus 9 metre​

Answer 1

Answer : The circumference of second orbit of H-atom is, $10^{-8}m$

Explanation : Given,

Wavelength of electron = $5\times 10^{-9}m$

The Bohr's formula is :

$2\pi r=n\lambda$

where,

r = radius of hydrogen atom

n = number of orbit = 2

$\lambda$ = wavelength of electron

$2\pi r$ = circumference of hydrogen atom

Now put all the given values in the above formula, we get the circumference of hydrogen atom.

$2\pi r=2\times (5\times 10^{-9}m)=1\times 10^{-8}m$

Therefore, the circumference of second orbit of H-atom is, $10^{-8}m$

Answer 2

Answer:

this will help you....