The circumference of the 5th Bohr orbit for the hydrogen atom is found to be n times the de Broglie wavelength
associated with the electron in that orbit. Determine the value of n.
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Answer:
5
Explanation:
according to bohr quantisation of angular momentum,
mvr = kh/2pie
=>2pie r = kh/mv
=>n(lambda) = 5(lambda) (given)
=>n = 5
i hope this will help you!!!!
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