The circumference of the base of a 12m high wooden solid cone is 44m. Find its volume
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Answered by
24
circumference =2 πr
44 = 44/7 × r
r = 7 cm
volume of wooden solid cone = πr²h/3
= 22/7 (7)² x 12/3
=22 x 7 x 4
=22 x 28
=616 cm²
44 = 44/7 × r
r = 7 cm
volume of wooden solid cone = πr²h/3
= 22/7 (7)² x 12/3
=22 x 7 x 4
=22 x 28
=616 cm²
Answered by
9
Given,
The circumference of the cone is 44m
Height of the cone 12m
Let's think the radius is r
We know that circumference of the cone is 2πr
Now,
2πr = 44
or, 2× 22/7 × r = 44
or, r = 44 × 7/22 × 2
or, r = 7
The volume of a cone is 1/3πr^2h
So the volume should be= 1/3 × 22/7 × 7× 7 × 12
The volume is = 616m^3
Then the answer is 616m^3
Hope it helps.
The circumference of the cone is 44m
Height of the cone 12m
Let's think the radius is r
We know that circumference of the cone is 2πr
Now,
2πr = 44
or, 2× 22/7 × r = 44
or, r = 44 × 7/22 × 2
or, r = 7
The volume of a cone is 1/3πr^2h
So the volume should be= 1/3 × 22/7 × 7× 7 × 12
The volume is = 616m^3
Then the answer is 616m^3
Hope it helps.
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