The circumference of the base of a 12m high wooden solid cone is 44m. Find the volume of cone and total surface area.
Please answer this question urgently. My exam is on 20th Thursday.
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height (h)= 12m
circumference = 44m
2πr = 44
2×22/7 × r = 44
radius (r) = 7m
slant height (l) =√ r^2+h^2
=√7^2+12^2
=√49 + 144
=√193
=13.89
Volume = 1/3 πr^2h
= 1/3 × 22/7 × 12 × 7 ×7
=22 × 4 × 7
= 616m^3
TSA = πr (l+r)
=22/7 × 7 (13.89 + 7 )
= 22 (20.89 )
= 459.58 m^2
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☺ HOPE IT HELPS YOU ☺
__________________________________
height (h)= 12m
circumference = 44m
2πr = 44
2×22/7 × r = 44
radius (r) = 7m
slant height (l) =√ r^2+h^2
=√7^2+12^2
=√49 + 144
=√193
=13.89
Volume = 1/3 πr^2h
= 1/3 × 22/7 × 12 × 7 ×7
=22 × 4 × 7
= 616m^3
TSA = πr (l+r)
=22/7 × 7 (13.89 + 7 )
= 22 (20.89 )
= 459.58 m^2
_________________________________-
☺ HOPE IT HELPS YOU ☺
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