The circumference of the base of a 8m high conical tent is 264÷4 m².the area of canvas required to make the tent is
Answers
Step-by-step explanation:
according according to your question and answer 569 metre squared cause you have when the circumference of the day
Answer:
937.2 (according to this question)
Step-by-step explanation:
So if you're question has the perimeter 264/7 m^2 then the answer is 1320/7 m^2. But according to this question, first you have to find the radius and for that we will do the following
2πr = 264/4m^2
r = 264 x 7/4 x 2 x 22
r = 21/2
So the formula of curved surface area of the tent (cone) is
πrl
To find out l we do the following
l = √r^2 + h^2
l = √21/2^2 + 8^2
l = √441/4 + 64
l = √697/4
l = 28.4 (approx)
Now the area required will be
πrl = 22/7 x 21/2 x 284/10 (if you take 28.4 in p/q form)
If you calculate this you will get approximately 937.2 m^2
Hope it helps.