Question

the circumference of the base of a cone 44cm and its slant height is 25cm. find the volume and c.s.a of the cone

Answer 1

Volume is 1232m3 and c.s.a is 550

Answer 2

circumference =2πr
44=2×22/7×r
22=22/7×r
$22 = \frac{22}{7} r \\ 22 \times 7 = 22r \\ \frac{22 \times 7}{22} = r \\ r = 7$
CSA of cone=πrl
=22/7×7×25
=550
Now ,
${l}^{2} = {r}^{2} + {h}^{2} \\ {25}^{2} = {7}^{2} + {h}^{2} \\ 625 - 49 = {h}^{2} \\ 576 = {h}^{2} \\ h = 24$
$volume \: of \: a \: cone = \frac{1}{3} \pi {r}^{2} h \\ = \frac{1}{3} \times \frac{22}{7} \times 7 \times 7 \times 24 \\ = \frac{1}{3} \times 22 \times 7 \times 24 \\ = 22 \times 7 \times 8 \\ = 1232$
I hope it helps you.