the circumference of the base of a cone is 220/7cm . its slant height is 13 cm .find the volume of the cone
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Hello friends!!
Here is ur answer :
First, the formula used in this question :
Circumference of base :
![2\pi r 2\pi r](https://tex.z-dn.net/?f=2%5Cpi+r)
Height of cone :
![\sqrt{ {l}^{2} - {r}^{2} } \sqrt{ {l}^{2} - {r}^{2} }](https://tex.z-dn.net/?f=+%5Csqrt%7B+%7Bl%7D%5E%7B2%7D++-+%7Br%7D%5E%7B2%7D++%7D+)
Volume of cone :
![\frac{1}{ 3} \pi {r}^{2} h \frac{1}{ 3} \pi {r}^{2} h](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+3%7D+%5Cpi+%7Br%7D%5E%7B2%7D+h)
Now come to the question :
Circumference of base of a cone = 220 / 7 cm
We have to find radius of cone.
Let the radius be r.
![2\pi r = \frac{220}{7} 2\pi r = \frac{220}{7}](https://tex.z-dn.net/?f=2%5Cpi+r+%3D++%5Cfrac%7B220%7D%7B7%7D+)
![\pi = \frac{22}{7} \pi = \frac{22}{7}](https://tex.z-dn.net/?f=%5Cpi+%3D++%5Cfrac%7B22%7D%7B7%7D+)
![2 \times \frac{22}{7} \times r = \frac{220}{7} 2 \times \frac{22}{7} \times r = \frac{220}{7}](https://tex.z-dn.net/?f=2+%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+r+%3D++%5Cfrac%7B220%7D%7B7%7D+)
![r = \frac{220}{7} \times \frac{7}{22} \times \frac{1}{2} r = \frac{220}{7} \times \frac{7}{22} \times \frac{1}{2}](https://tex.z-dn.net/?f=r+%3D++%5Cfrac%7B220%7D%7B7%7D++%5Ctimes++%5Cfrac%7B7%7D%7B22%7D++%5Ctimes++%5Cfrac%7B1%7D%7B2%7D+)
![r = \frac{10}{2} r = \frac{10}{2}](https://tex.z-dn.net/?f=r+%3D++%5Cfrac%7B10%7D%7B2%7D+)
![r = 5 r = 5](https://tex.z-dn.net/?f=r+%3D+5)
Therefore, radius r of cone = 5 cm
Slant height l of cone = 13 cm
We have to find height of cone.
Let the height be h.
Using formula,
![{l}^{2} = {r}^{2} + {h}^{2} {l}^{2} = {r}^{2} + {h}^{2}](https://tex.z-dn.net/?f=+%7Bl%7D%5E%7B2%7D++%3D++%7Br%7D%5E%7B2%7D++%2B++%7Bh%7D%5E%7B2%7D+)
![{(13)}^{2} = {(5)}^{2} + {h}^{2} {(13)}^{2} = {(5)}^{2} + {h}^{2}](https://tex.z-dn.net/?f=+%7B%2813%29%7D%5E%7B2%7D++%3D++%7B%285%29%7D%5E%7B2%7D+++%2B++%7Bh%7D%5E%7B2%7D+)
![169 = 25 + {h}^{2} 169 = 25 + {h}^{2}](https://tex.z-dn.net/?f=169+%3D+25+%2B++%7Bh%7D%5E%7B2%7D+)
![{h}^{2} = 169 - 25 {h}^{2} = 169 - 25](https://tex.z-dn.net/?f=+%7Bh%7D%5E%7B2%7D++%3D+169+-+25)
![{h}^{2} = 144 {h}^{2} = 144](https://tex.z-dn.net/?f=+%7Bh%7D%5E%7B2%7D++%3D+144)
![h = \sqrt{144} h = \sqrt{144}](https://tex.z-dn.net/?f=h+%3D+++%5Csqrt%7B144%7D+)
![h = 12 h = 12](https://tex.z-dn.net/?f=h+%3D+12)
Height h of cone = 12 cm
Volume of cone :
![= \frac{1}{3} \times \frac{22}{7} \times {(5)}^{2} \times 12 = \frac{1}{3} \times \frac{22}{7} \times {(5)}^{2} \times 12](https://tex.z-dn.net/?f=+%3D++%5Cfrac%7B1%7D%7B3%7D++%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes++%7B%285%29%7D%5E%7B2%7D++%5Ctimes+12)
![= 1 \times \frac{22}{7} \times 25 \times 4 = 1 \times \frac{22}{7} \times 25 \times 4](https://tex.z-dn.net/?f=+%3D++1+%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+25+%5Ctimes+4)
![= \frac{2200}{7} = \frac{2200}{7}](https://tex.z-dn.net/?f=+%3D++%5Cfrac%7B2200%7D%7B7%7D+)
![= 314.285714 \: \: {cm}^{3} = 314.285714 \: \: {cm}^{3}](https://tex.z-dn.net/?f=+%3D+314.285714+%5C%3A++%5C%3A++%7Bcm%7D%5E%7B3%7D+)
HOPE IT HELPS YOU..
Here is ur answer :
First, the formula used in this question :
Circumference of base :
Height of cone :
Volume of cone :
Now come to the question :
Circumference of base of a cone = 220 / 7 cm
We have to find radius of cone.
Let the radius be r.
Therefore, radius r of cone = 5 cm
Slant height l of cone = 13 cm
We have to find height of cone.
Let the height be h.
Using formula,
Height h of cone = 12 cm
Volume of cone :
HOPE IT HELPS YOU..
abhi569:
Excellent
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