the circumference of the base of a cylinder is 88 cm and its height is 40 cm.Find its total surface area....plz plz plz solve this fast
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Answer:
Total surface area= 4752 sq. cm
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Let the base radius of the cylinder be r cm.
Height of its base = 60 cm
Circumference of its base = 88cm
circumference=2πr
88=2*22/7*r
r=88*7/2*22
=>r=14
Therefore, the radius is 14 cm.
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Volume of the cylinder
=πr²h
22/7*(14)²*40
=3690cm
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CSA \: \: \: \: of \: \: \: \: the \: \: \: \: \: cylinderCSAofthecylinder
\begin{lgathered}= 2\pi \: rh \\ \\ =( 2 \times \frac{22}{7} \times 14 \times 60) \: \: {cm}^{2} \\ \\ = 5280 \: \: {cm}^{2}\end{lgathered}
=2πrh
=(2×
7
22
×14×60)cm
2
=5280cm
2
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