Question

the circumference of the base of a cylinder is 88 cm and its height is 60 cm.find the volume of the cylinder and its curved surface area....plz plz plz solve this fast

Answer 1

circumference = 2πr = 88 (given)
so, 2× π × r = 88
π×r = 88 / 2
22/7 × r = 44
r= (44×7) / 22
r= 2×7
r= 14cm
Volume= πr²h
=(22/7) × 14×14 × 60 (h=60)
=44×14×60
=36960 cm³
C.S.A. = 2πrh
= 2× [22/7] ×14 × 60
=88×60 (2πr = 88 [given])
=5280 cm²

Answer 2

Solution ●●●●
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Let the base radius of the cylinder be r cm.

Height of its base = 60 cm

Circumference of its base = 88 cm

$= > 2\pi \: r = 88$

$= > 2 \times \frac{22}{7} \times r = 88 \\ \\ = > 44r = 88 \times 7 \\ \\ = > r = \frac{88 \times 7}{44} \\ \\ = > r = 14 \: \:$

Therefore, the radius is 14 cm.
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$Volume \: \: \: \: of \: \: \: \: the \: \: \: \: cylinder$

$= \pi {r}^{2} h \\ \\ = ( \frac{22}{7} \times 14 \times 14 \times 60) \: \: {cm}^{3} \\ \\ = 3690 \: \: {cm}^{3}$
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$CSA \: \: \: \: of \: \: \: \: the \: \: \: \: \: cylinder$

$= 2\pi \: rh \\ \\ =( 2 \times \frac{22}{7} \times 14 \times 60) \: \: {cm}^{2} \\ \\ = 5280 \: \: {cm}^{2}$
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I hope it will help you
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